This read-only map returns the logical 'and' of the values of the two given maps. Its Key type is inherited from M1 and its Value type is bool. M2::Key must be convertible to M1::Key.
If m1 is of type M1 and m2 is of M2, then for
am[x] will be equal to m1[x]&&m2[x].
The simplest way of using this map is through the andMap() function.
#include <lemon/maps.h>
Inheritance diagram for AndMap< M1, M2 >:Public Types | |
| typedef M1::Key | Key |
| | |
| typedef bool | Value |
| | |
Public Types inherited from MapBase< M1::Key, bool > | |
| typedef M1::Key | Key |
| The key type of the map. | |
| typedef bool | Value |
| The value type of the map. (The type of objects associated with the keys). | |
Public Member Functions | |
| AndMap (const M1 &m1, const M2 &m2) | |
| Constructor. | |
| Value | operator[] (const Key &k) const |
| | |
Related Functions | |
(Note that these are not member functions.) | |
| template<typename M1 , typename M2 > | |
| AndMap< M1, M2 > | andMap (const M1 &m1, const M2 &m2) |
Returns an AndMap class. More... | |
1.8.5